3w^2+12w+9=(3w+1)(-3w-1)+

Solution for 3w^2+12w+9=(3w+1)(-3w-1)+ equation:

3w^2+12w+9=(3w+1)(-3w-1)+

We move all terms to the left:

3w^2+12w+9-((3w+1)(-3w-1)+)=0

We multiply parentheses ..

3w^2-((-9w^2-3w-3w-1)+)+12w+9=0


We calculate terms in parentheses: -((-9w^2-3w-3w-1)+), so:

(-9w^2-3w-3w-1)+

We add all the numbers together, and all the variables

(-9w^2-3w-3w-1)

We get rid of parentheses

-9w^2-3w-3w-1

We add all the numbers together, and all the variables

-9w^2-6w-1

Back to the equation:

-(-9w^2-6w-1)


We get rid of parentheses

3w^2+9w^2+6w+12w+1+9=0

We add all the numbers together, and all the variables

12w^2+18w+10=0

a = 12; b = 18; c = +10;
Δ = b2-4ac
Δ = 182-4·12·10
Δ = -156
Delta is less than zero, so there is no solution for the equation